Oh sorry I didn't see the reply...
The formula I use is as follows:
The number of pages for the first coverage range * coverage (see example 1) + number of pages for the second coverage range * coverage + next and so on. Divide the sum with the sum of total number of pages, that gives you a "high" average.
Example 1
This is what the machine log displays:
Coverage 0-2%: 5000 pages
Coverage 3-5%: 15000 pages
Coverage 6-10%: 6000 pages
Coverage 11-20%: 2000 pages
Coverage 21- < : 1000 pages
(5000 * 2 = 10000) + (15000 * 5 = 75000) + (6000 * 10 = 60000) + (2000 * 20 = 40000) + (1000 * 21 = 21000) = 206000
206000 / total of 29000 pages = 7,10%
Now 7,10% is pretty high since we're using the highest percentage in the range, i.e. 6000 * 10 instead of 6, 7, 8 or 9 which is in the same range. This is a worst-case-scenario number. To bring justice into the equation, you need to calculate the lowest possible number as well, which then becomes example 2:
(5000 * 1 = 5000) + (15000 * 3 = 45000) + (6000 * 6 = 36000) + (2000 * 11 = 22000) + (1000 * 21 = 21000) = 129000
129000 / total of 29000 pages = 4,45%.
Then add the two numbers together (7,10 + 4,45 = 11,55) and divide in 2 and you've got yourself 5,775% coverage, which is probably pretty close to the truth.
Hope that's mathematic enough for ya
The formula I use is as follows:
The number of pages for the first coverage range * coverage (see example 1) + number of pages for the second coverage range * coverage + next and so on. Divide the sum with the sum of total number of pages, that gives you a "high" average.
Example 1
This is what the machine log displays:
Coverage 0-2%: 5000 pages
Coverage 3-5%: 15000 pages
Coverage 6-10%: 6000 pages
Coverage 11-20%: 2000 pages
Coverage 21- < : 1000 pages
(5000 * 2 = 10000) + (15000 * 5 = 75000) + (6000 * 10 = 60000) + (2000 * 20 = 40000) + (1000 * 21 = 21000) = 206000
206000 / total of 29000 pages = 7,10%
Now 7,10% is pretty high since we're using the highest percentage in the range, i.e. 6000 * 10 instead of 6, 7, 8 or 9 which is in the same range. This is a worst-case-scenario number. To bring justice into the equation, you need to calculate the lowest possible number as well, which then becomes example 2:
(5000 * 1 = 5000) + (15000 * 3 = 45000) + (6000 * 6 = 36000) + (2000 * 11 = 22000) + (1000 * 21 = 21000) = 129000
129000 / total of 29000 pages = 4,45%.
Then add the two numbers together (7,10 + 4,45 = 11,55) and divide in 2 and you've got yourself 5,775% coverage, which is probably pretty close to the truth.
Hope that's mathematic enough for ya

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